What is the molarity of 930 mL LiCl solution that contains 139.9 g LiCl?

Here's how to calculate the molarity of the LiCl solution:

1. Calculate the moles of LiCl:

* Molar mass of LiCl: 6.941 g/mol (Li) + 35.453 g/mol (Cl) =42.394 g/mol

* Moles of LiCl: (139.9 g LiCl) / (42.394 g/mol) =3.30 mol LiCl

2. Convert volume to liters:

* Volume in liters: 930 mL * (1 L / 1000 mL) =0.930 L

3. Calculate molarity:

* Molarity (M): (moles of solute) / (volume of solution in liters)

* Molarity: (3.30 mol LiCl) / (0.930 L) =3.55 M

Therefore, the molarity of the LiCl solution is 3.55 M.